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Question

Find tn for the following A.P.s
4,9,14,19.....

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Solution

General term AP is given by
tn=a+nd
t1=a+2d
4=a+d(1)
t2=a+2d
9=a+2d(2)
Subtract (1) and (2),
94 (2dd)+(aa)
a+d=4
a+5=4
a1
tn=5n1


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