Question

Find t₁₁ from the following A.P. 4, 9, 14, ....

Answer 1

In the given A.P., we have:
a = 4 and d = t₂ – t₁ = 9 – 4 = 5
We know that the nth term of an A.P., is t_n = a + (n – 1)d.
To find the 11^th term of the given A.P., we need to take n = 11.
Thus, we get:
t₁₁ = 4 + (11 – 1)5
= 4 + 10 × 5
= 4 + 50
= 54
Therefore, the 11^th term of the given A.P. is 54.