Question

Find ten rational number between $\frac{-3}{11}$ and $\frac{8}{11}$

Answer 1

We know that
$-3<-2<-1<0<1<2<3<4<5<6<7<8$ This gives us $10$ integers between $-3$ and $-8$
So, $\frac{-2}{11},\frac{-1}{11},0,\frac{1}{11},\frac{2}{11},\frac{3}{11},\frac{4}{11},\frac{5}{11},\frac{6}{11},\frac{7}{11}$ are the ten desired rational numbers.