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Question

Find th H.C.F of 3xy2z3, 3yz2x2 and x2y2z


A

x2yz

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B

3xy2z3

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C

xyz

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D

x2y2z

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Solution

The correct option is C

xyz


If the three given quantitis, the common elementary factors are x, y and z. The highest powers of x, y, z that exactly divide the quantities are x, y, z


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