Find the 10th term of the AP : 2, 7, 12, . . .
57
52
47
42
Here, a = 2, d = 7 – 2 = 5 and n = 10.
We have an = a + (n – 1) d
So, a10 = 2 + (10 – 1) × 5 = 2 + 45 = 47
Therefore, the 10th term of the given AP is 47.