Question

Find the ${10}^{th}$ term of the series ${1.2}^2+{2.3}^2+{3.4}^2+-------nterms$

• A. 121
• B. 1211
• C. 1210
• D. 1220

Answer 1

The correct option is C

1210

${1.2}^2+{2.3}^2+{3.4}^2+-------nterms$

$n^{th}$ term of the series = {nth term of series 1,2,3,.......... } $\times$ {$nthtermofseries{2}^2,3^2,4^2,..........$}

$T_n$ = n$(n+1{)}^2$

$T_{10}$ = 10 $\times$ ${11}^2$ = 1210

=1210