Question

Find the $1000$th term of the sequence $3,4,5,6$, ..........

Answer 1

We know that the formula for the nth term is $t_n=a+(n-1)d$, where $a$ is the first term, $d$ is the common difference.

It is given that the first term $a=3$, the common difference $d=4-3=1$ and $n=1000$, therefore,

$t_{1000}=3+(1000-1)1=3+999=1002$

Hence, the $1000$th term of the sequence is $1002$.