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Question

Find the 10th term from the end of the A.P. 8,10,12,...,126.

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Solution

126 = 8+(n-1)2
118 = (n-1)2
59 = n-1
n = 60

the pth term from the last

t(n-p+1) = a+(n-p)d
t(60-10+1) = 8 +(60-10)2
t51 = 108

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