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Question
Find the 10th term of an A.P. −1.0,−1.5,−2.0.
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Solution
Given,
a=−1.0
d=−1.5−(−1.0)=−0.5
Formula:
Tn=a+(n−1)d
T10=−1.0+(10−1)(−0.5)
=−1.0−4.5
=−5.5
Given,
a=−1.0
d=−1.5−(−1.0)=−0.5
Formula:
Tn=a+(n−1)d
T10=−1.0+(10−1)(−0.5)
=−1.0−4.5
=−5.5
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