Question

Find the ${11}^{th}$ term from the end in the $AP56,63,70,...,329$.

Answer 1

The terms $56,63,70,...,329$ are in A.P

where $a=56$ and $d=63-56=70-63=7$

Last term $l=329$

${11}^{th}$ term$=a+10d=56+10\times 7=56+70=126$

$\therefore {11}^{th}$ term is $126$