Question

Find the 11th term from the last term towards the first term of the AP 10, 7, 4,.... (−62).

Answer 1

Here, a = 10 and d = (7 - 10) = -3, l = (-62) and n = 11

Now, n^th term from the end = [l - (n - 1)d]
11^th term from the end = [(-62) - (11 - 1) ⨯ (-3)]
= [-62 + (10 ⨯ 3)] = (-62 + 30) = -32

Hence, the 11^th term from the last towards the first term of the AP is -32.