Question

Find the ${12}^{th}$ term of G.P $3,6,12,24,......$.

Answer 1

$3,6,12,24,...,3072$ are in G.P

$\Rightarrow \frac{6}{3}=\frac{12}{6}=\frac{24}{12}=2$

$\therefore a=3,r=2$

${12}^{th}$ term$=a{r}^{12-1}=a{r}^{11}=3\times 2^{11}=3\times 2048=6,144‬$