Find the 12th term of the AP. whose first term is 9 and common difference is 10.

110

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119

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128

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130

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Solution

The correct option is B 119
The nth term in an AP is given by $t_{n} = a + (n - 1) d$ , where 'a' is the first term, 'n' the number of terms and 'd' is the common difference.
So, the 12th term would be $t_{12} = 9 + (12 - 1) 10 ⟹ t_{12} = 9 + 110 ⟹ t_{12} = 119$

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Find the 12th term of the AP. whose first term is 9 and common difference is 10.

The correct option is B 119The nth term in an AP is given by tn=a+(n−1)d, where 'a' is the first term, 'n' the number of terms and 'd' is the common difference.So, the 12th term would be t12=9+(12−1)10⟹t12=9+110⟹t12=119

The correct option is B 119
The nth term in an AP is given by $t_{n} = a + (n - 1) d$ , where 'a' is the first term, 'n' the number of terms and 'd' is the common difference.
So, the 12th term would be $t_{12} = 9 + (12 - 1) 10 ⟹ t_{12} = 9 + 110 ⟹ t_{12} = 119$