Find the $15^{t h}$ term of the G.P. 3, 12, 48, 192, ..........

3 \times 4^{15}

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3 \times 4^{14}

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3 \times 4^{16}

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3^{15}

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Solution

The correct option is B $3 \times 4^{14}$
Clearly, the given GP has first term $a = 3$ and common ratio $r = 4$ .
$∴ a_{15} = a r^{14}$
$=> a_{15} = 3 \times (4)^{14}$

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Similar questions

3, 12, 48, 192, ?

12^{t h}

3, 6, 12, 24, . . . . . .

\frac{3 + \sqrt{12} - \sqrt{27}}{7 + \sqrt{192} - \sqrt{48}} = a + b \sqrt{3},

\frac{3 + \sqrt{12} - \sqrt{27}}{7 + \sqrt{192} - \sqrt{48}} = a + b \sqrt{3}

a

b

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