Find the 19 th term of the following sequence-tn n2- when n is even n2-1 when n is odd

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Solving a Quadratic Equation by Factorization Method

Find the 19 t...

Question

Find the 19th term of the following sequence:

tn (n² when n is even)

( n2-1 when n is odd)

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1^{2} + {2.2}^{2} + 3^{2} + {2.4}^{2} + 5^{2} + {2.6}^{2} + \dots . i s \frac{n}{2} (n + 1)^{2}

\forall n ϵ N, n^{2} + n

n^{2} - n

median = value of (\frac{n + 1}{2}) th

median = \frac{1}{2} \times \{value of \frac{n}{2} th item + value of (\frac{n}{2} + 1) th item\}

Mode = \frac{1}{2} (mean + median)

If $n$ is odd, then $1 + 3 + 5 + 7 + . . . . . +$ to $n$ terms is equal to

(a) $(n^{2} + 1)$

(b) $(n^{2} - 1)$

(d) $(2 n^{2} + 1)$

n

a_{n} = n^{2} - n + 1

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