Given A.P. is:
3, 8, 13, …, 253
Common difference of this A.P. is 5.
Therefore, this A.P. can be written in reverse order as;
253, 248, 243, …, 13, 8, 5
For this A.P,
a = 253
d = 248 − 253 = −5
n = 20
a20=a+(20−1)da20=253+(19)(−5)a20=253−95a=158
Therefore, 20th term from the last term is 158.