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Question

Find the 20th term of an A.P. whose 5th term is 15 and the sum of its 3rd and 8th terms is 34.

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Solution

t5=t5 and t3+t8=34
a+4d=15 ...(i)
and (a+2d)+(a+7d)=34
2a+9d=34 ...(ii)
(i) and (ii) gives d=4 and a=1
t20=a+19d=1+19×4=75

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