Find the $20^{t h}$ term of the sequence whose $n t h$ term is $a_{n} = \frac{n (n - 2)}{n + 3}$ .

\frac{260}{23}

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\frac{360}{23}

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\frac{240}{23}

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\frac{350}{23}

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Solution

The correct option is B $\frac{360}{23}$
$a_{n}$ = $\frac{n (n - 2)}{n + 3}$
Putting $n = 20$ , we obtain a $_{20}$ = $\frac{20 (20 - 2)}{20 + 3}$
Thus $a_{20}$ = $\frac{360}{23}$

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