Find the $20 t h$ term from the last term of the AP $3, 8, 13, . . . .253 .$

156

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180

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158

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188

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Solution

The correct option is C $158$
The AP is $3, 8, 13, . . . ., 253$
Its first term $= 3$ and the common difference $= 5$
The AP in the reverse order will have the first term $= 253$ and the common difference $= - 5$
The $20 t h$ term from the end of the given AP $=$ The $20 t h$ term of the AP in the reverse order $= a + 19 d$
$= 253 + 19 \times (- 5) = 253 - 95 = 158$

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20

: 3, 8, 13, . . ., 253.

Find the 20^th term from the last term of the A.P. 3, 8, 13, …, 253

20^{t h}

A . P .3, 8, 13.........253

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