Question

Find the $30$ th term of the A.P : $10,7,\mathrm{4....}$

Answer 1

here,

$a=10$

$d=-3$

$a_n=a+\left(n-1\right)d{a}_{30}=10+\left(30-1\right)\left(-3\right)=10+29\left(-3\right)=10-87=-77$

Thus 30th term would be -77

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