Question

Find the 300^th term in the series A26, B25, B25, C24, C24, C24 , D23, $\dots \dots$

• A. W4
• B. X3
• C. Y2
• D. None of these

Answer 1

The correct option is B

X3

In the series, A occurs once, B occurs twice, C occurs thrice and so on. Total number of terms till Z, which occurs 26 times = 1 + 2 + 3 + 4 +..26 = 351. Moving backwards, Z occurs from term 326 to term 351(26 terms), Y occurs from term 301 to term 325 (25 terms). Therefore 300^th term would be X. A is assigned a number 26. B is asssigned 25 and so on. Therefore, X would be assigned 3.