Find the 31 st term of an A.P . whose 10 th term is 31 and the 15th terms is 66

Open in App

Solution

Formula,

$a_{n} = a + (n - 1) d$

Given,

$a_{10} = a + 9 d = 31$ .........(1)

$a_{15} = a + 14 d = 66$ .........(2)

solving (1) and (2), we get,

$d = 7, a = - 32$

$a_{31} = a + 30 d$

$= - 32 + 30 (7)$

$= 178$

Suggest Corrections

Similar questions

31

11

38

16

73

31^{s t}

11^{t h}

38

16^{t h}

73

The $31^{s t}$ term of an AP whose $11^{t h}$ term is 38 and $16^{t h}$ term is 73 is....

Find the $31^{s t}$ term of an A. P. whose $10^{t h}$ term is $38$ and $16^{t h}$ term is $74$ .

31^{s t}

16^{t h}

Join BYJU'S Learning Program