Find the $50^{t h}$ term of the given arithmetic series: $4 + 9 + 14 + 19 + . . . .$

149

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249

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349

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449

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Solution

The correct option is B $249$
$a_{n} = a + (n - 1) d$
$\Rightarrow a_{50} = 4 + (50 - 1) 5$
$\Rightarrow a_{50} = 4 + 245$
$\Rightarrow a_{50} = 249$

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