Find the $5 t h$ term from the end of the $A P 7, 10, 13, . .154$

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Solution

Given that:
$A P : 7, 10, 13, . . . ., 154$
Let the $d$ be common difference then
$d = 10 - 7 = 13 - 10$
$d = 3, a = 7, L = 154$
Now,

$T_{n} = a + d (n - 1)$

$T_{5} = 7 + 3 (5 - 1)$

$T_{5} = 19 .$

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