Question

Find the 5th term of the sequence $1,\sqrt{2},\mathrm{2...}$

• A. 1
• B. 2
• C. 3
• D. 4

Answer 1

Answer: (D)

4

From given GP, we have $a=1,$ common ratio$,r=$ $\sqrt{2}$
We know the formula for nth term,
$a_n=a{r}^{n-1}$
$a_5=1\times (\sqrt{2}{)}^{5-1}$
$a_5=1\times (\sqrt{2}{)}^4$
$a_5=1\times 4$
$a_5=4$