Question

Find the $6^{th}$
term from the end of the A.P : $17,14,11,......-40$

Answer 1

◆ Given,

• AP... 17,14,11..-40
  
• So, now we need the 6th term from last. SO, by reversing the AP, we get;
  
• AP = -40,-37,-31......14,17
  

Now, Given;

• d=3
  
• a1=-40
  
• n=6
  
• Therefore a6= a+(n-1)d
  

$=a_6=-40+(6-1)3$

$=a_6=-40+5\ast 3$

$=a_6=-40+15$

$=a_6=-25$

So the 6th term is$-25$