Find the $6^{t h}$ term from the last term of the A.P. $17, 14, 11,$ ________, $- 40$ .

Open in App

Solution

$A . P = 17, 14, 11 F i r s t t e r m = 17 C o m m o n d i f f e r e n c e = 14 - 17 = - 3 L a s t t e r m = - 40 ∴ 6 t h t e r m f r o m t h e e n d = l - (6 - 1) d = - 40 - (5) \times - 3 = - 40 + 15 = - 25 A n s .$

Suggest Corrections

Similar questions

6^{t h}

17, 14, 11, . . . . . . - 40

5^{t h}

A . P . : 17, 14, 11, . . . . . . ., - 40

6^{t h}

17, 14, 11, . . . - 10

17, 14, 11, . . . . . . ., - 40

Find the $6^{t h}$ term from the end of the AP 17, 14, 11,...., -40.

Join BYJU'S Learning Program