Question

Find the $6^{th}$ term of the H.P. $\frac{1}{11},\frac{1}{14},\frac{1}{17},\frac{1}{20}.....$

• A. $\frac{1}{13}$
• B. $\frac{1}{26}$
• C. $\frac{1}{38}$
• D. $26$

Answer 1

Answer: (B)

$\frac{1}{26}$

The reciprocal of A.P. is H.P.
A.P. is in the form of $11,14,17,\mathrm{20...}$
So, common difference in AP is $3$
So, $6^{th}$ term of the AP is
$a_n=a+(n-1)d$
$a_6=11+(6-1)3$
$=11+15$
$=26$
Therefore, $6^{th}$ term of HP is $\frac{1}{26}$.