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Question

Find the 6th term of the sequence: 3, 9, 27, 81…


A
243
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B
729
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C
339
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D
999
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Solution

The correct option is B 729

The given sequence is 3, 9, 27, 81…

Let us divide each term of the sequence by the term preceding it:

9÷3=3

27÷9=3

81÷27=3

We observe that each term in the sequence is 3 times the term preceding it.

The 4th term of the sequence = 81

The 5th term of the sequence = 3×(4th term of the sequence) = 3×81 = 243.

So, the 6th term of the sequence = 3×(5th term of the sequence) = 3×243 = 729.


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