Find the 6th term of the sequence: 3, 9, 27, 81…
The given sequence is 3, 9, 27, 81…
Let us divide each term of the sequence by the term preceding it:
9÷3=3
27÷9=3
81÷27=3
We observe that each term in the sequence is 3 times the term preceding it.
The 4th term of the sequence = 81
The 5th term of the sequence = 3×(4th term of the sequence) = 3×81 = 243.
So, the 6th term of the sequence = 3×(5th term of the sequence) = 3×243 = 729.