In the given G.P., we have t1 = 1, t2 = –1, t3 = 1 and t4 = –1.
Thus, we have the first term, i.e., a = t1 = 1, and the common ratio, i.e., .
We know that the nth term of the G.P. is tn = arn – 1.
By taking a = 1, r = –1 and n = 69, we have:
t69 = (1)(–1)69 – 1
t69 = (1)(–1)68
t69 = 1 × 1 = 1
Thus, the 69th term is 1.