Find the 6th term from the end of the AP 5, 7, 9, ...., 201.
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Solution
Here, a = 5, d = (7 - 5) = 2, l = 201 and n = 6th
Now, nth term from the end = [l - (n - 1)d]
6th term from the end = [201 - (6 - 1) ⨯ 2]
= [201 - (5 ⨯ 2)] = (201 - 10) = 191
Hence, the 6th term from the end of the AP is 191.