Find the $7^{t h}$ digit from the right in 25!

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Solution

The correct option is A 4
Solution:Option (b)

First find the number of zeros in $25! = (\frac{25}{5} = 5) + (\frac{25}{25} = 1) = 6$

To find the last non-zero digit at the end of 25!

1! to10! Ends with 8 (non-zero)

11! To 20! Also ends with 8

Hence $25! = 8 \times 8 \times 1 \times 2 \times 3 = . . . . .4$

(We don’t consider $24 \times 25$ as it will end in a zero.)

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