Question

Find the $7^{th}$ term from the end in expansion of ${(x-\frac{2}{x^2})}^{10}$

Answer 1

$7^{th}termfromendwillbe=(10+1-7{)}^{th}term=4^{th}termfrombegining\therefore T_4{=}^{10}{C}_3(x{)}^7\left(\right(\frac{-2}{x^2}\left){)}^3{=}^{10}{C}_3{x}^7\right(\frac{-8}{x^6}\left){=}^{10}{C}_3\right(-8x)=-960x$