Question

Find the $7^{th}$ term from the last in the G.P $2,4,8,16,...60$ terms

Answer 1

Given series is $2,4,8,16,...60$ terms

First term$a=2$

Common ratio$=\frac{4}{2}=2$

$7^{th}$ term from the last in G.P$={(60-7+1)}^{th}$ term from the beginning$={54}^{th}$ term.

$\therefore t_{54}=a{r}^{54-1}$

$t_{54}=a{r}^{53}$

$t_{54}=2\times 2^{53}$

$t_{54}=2^{54}$