Find the $7^{t h}$ term of the sequence whose $n^{t h}$ term is $a_{n} = \frac{n^{2}}{2^{n}}$

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Solution

Given $n^{t h}$ term of the sequence is,
$a_{n} = \frac{n^{2}}{2^{n}}$
$\Rightarrow a_{7} = \frac{49}{2^{7}} = 0.3828125$

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