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Byju's Answer
Standard IX
Mathematics
(x±a)(x±b) = x²±(a+b)x+ab.
Find the 8th ...
Question
Find the 8th term in the expansion of
x
3
/
2
y
1
/
2
-
x
1
/
2
y
3
/
2
10
.
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Solution
We need to find the 8th term in the given expression.
∵
T
8
=
T
7
+
1
∴
T
8
=
C
7
10
(
x
3
/
2
y
1
/
2
)
10
-
7
(
-
x
1
/
2
y
3
/
2
)
7
=
-
10
×
9
×
8
3
×
2
x
9
/
2
y
3
/
2
x
7
/
2
y
21
/
2
=
-
120
x
8
y
12
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0
Similar questions
Q.
Find the
8
t
h
term in the expansion of
(
x
3
/
2
y
1
/
2
−
x
1
/
2
y
3
/
2
)
10
Q.
The term independent of x in the expansion of
(
x
+
1
x
2
3
−
x
1
3
+
1
−
x
−
1
x
−
x
1
2
)
10
is
Q.
Write the following transformation in matrix form
x
1
=
√
3
2
y
1
+
1
2
y
2
;
x
2
=
−
1
2
y
1
+
√
3
2
y
2
.
Hence find the transformation in matrix form which expresses
y
1
,
y
2
in terms of
x
1
,
x
2
.
Q.
The term independent of x expansion of
(
x
+
1
x
2
3
−
x
1
3
+
1
−
x
−
1
x
−
x
1
2
)
10
is
Q.
The term independent of
x
in expansion of
(
x
+
1
x
2
/
3
−
x
1
/
3
+
1
−
x
−
1
x
−
x
1
/
2
)
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is
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(x±a)(x±b) = x²±(a+b)x+ab.
Standard IX Mathematics
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