Question

Find the $9^{th}$ term of a G.P.: $3,6,12,24,....$

Answer 1

Hence we have $a=3,n=9,r=2$
Now $t_n=a{r}^{n-1}$
$t_9=3\times 2^{9-1}$
$=3\times 2^8$
$=3\times 256$
$=768$
$\therefore$ The ninth term of the G.P. is $768$.