Find the $9^{t h}$ term of an A.P $2, 5, 8, 11, . . . . . . .$

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Solution

Given A.P is $2, 5, 8, 11, . . . . . .$
$a = t_{1} = 2, t_{2} = 5, t_{3} = 8, . . . .$
Common difference, $d = t_{2} - t_{1} = 5 - 2 = 3$
Now, $t_{n} = a + (n - 1) d$
Thus, $9^{t h}$ term
$t_{9} = 2 + (9 - 1) 3$
$= 2 + 8 \times 3$
$= 2 + 24$
$= 26$

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