Find the 9th term in the expansion of 3x-1-2x8- x - 0-

The correct option is D 1256x^8 T_9=^8C_8(3x)^∘(( 1/2x)^8) =1×1× (1/2^8x^8)=(1/256x^8) ...

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Binomial Coefficients

Find the 9t...

Question

Find the $9 t h$ term in the expansion of ${(3 x - \frac{1}{2 x})}^{8}, x \neq 0.$

\frac{256}{x^{8}}

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\frac{(x^{8})}{256}

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\frac{1}{256 x^{8}}

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256 x^{8}

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