Find the 9th term of the harmonic sequence $1, - 1, - 3, - 5$ ..

- 15

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\frac{1}{- 15}

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\frac{1}{n - 15}

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\frac{1}{15}

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Solution

The correct option is B $\frac{1}{- 15}$
Given series is $1, - 1, - 3, - 5$
Here first term $= a = 1$ , common difference $= r = - 2$
We know $a_{n} = \frac{1}{a + (n - 1) d}$
$a_{9} = \frac{1}{1 + (9 - 1) (- 2)}$
$a_{9} = \frac{1}{- 15}$

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