Find the acceleration of a particle placed on the surface of the earth at the equator due to earth's rotation. The diameter of earth = 12800 km and it takes 24 hours for the earth to complete one revolution about its axis.
Diameter of earth = 12800 km
Radius of earth, R = 6400 km = 64×105 m
T = 24 hr = 24 × 3600 sec
v=2πrT=2×3.14×64×10524×3600=465.185α=v2R=(465.185)264×105 =0.038 m/sec2