Question

Find the acceleration of a particle placed on the surface of the earth at the equator due to earth's rotation. The diameter of earth = 12800 km and it takes 24 hours for the earth to complete one revolution about its axis.

Answer 1

Diameter of earth = 12800 km

Radius of earth, R = 6400 km = 64$\times {10}^5$ m

T = 24 hr = 24 $\times$ 3600 sec

$v=\frac{2\pi r}{T}=\frac{2\times 3.14\times 64\times {10}^5}{24\times 3600}=465.185\alpha =\frac{v^2}{R}=\frac{(465.185{)}^2}{64\times {10}^5}=0.038m/se{c}^2$