Find the acceleration of block if the wedge is at rest.

\frac{g}{2}

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\frac{g}{4}

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zero

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block will not slide

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Solution

The correct option is B $\frac{g}{4}$
$a = g s i n θ - μ g c o s θ = g \times \frac{1}{2} - \frac{1}{2 \sqrt{3}} g \frac{\sqrt{3}}{2} = \frac{g}{4}$

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Find the acceleration of block if the wedge is at rest.

The correct option is B g4a=gsinθ−μgcosθ=g×12−12√3g√32=g4

The correct option is B $\frac{g}{4}$
$a = g s i n θ - μ g c o s θ = g \times \frac{1}{2} - \frac{1}{2 \sqrt{3}} g \frac{\sqrt{3}}{2} = \frac{g}{4}$