Find the acceleration of the 3m block when the system is released from rest. All other surfaces are smooth except between m and 2m. Take g=10m/s2
A
a=3m/s2
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B
a=3.5m/s2
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C
a=5m/s2
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D
a=5.4m/s2
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Solution
The correct option is Da=5.4m/s2 The FBDs of the blocks are as shown
From the FBDs, we have N1=mg fmax=μN1=0.3mg and T=3mg
Assuming the system to move together with common acceleration, then it is given by a=(Supporting Force-Opposing Force)Total mass =3mg6m=g2
(since friction is an internal force)
From the FBD of block m we get f=mam=mg2=0.5mg
Since, f>fmax, our assumption is wrong.
The two blocks will separate and move with different accelerations.
So, acceleration of m is am=fmaxm=0.3mgm=0.3g=3m/s2
The acceleration of 2m and 3m will be same. So, from their FBDs, we have T−fmax=2ma1⇒T−0.3mg=2ma1 3mg−T=3ma1
From above two equations, we get 2.7mg=5ma1⇒a1=2.7g5 ⇒a1=275=5.4m/s2
Hence, the acceleration of 3m is 5.4m/s2