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Pseudo Force

Find the acce...

Question

Find the acceleration of the $500 g$ block shown in the figure.

A

\frac{8 g}{13}

downward

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B

\frac{g}{13}

upward

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C

\frac{8 g}{3}

downward

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D

\frac{8 g}{7}

upward

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Solution

The correct option is A $\frac{8 g}{13}$ downward
Let the acceleration of blocks be $a$ towards right.
From FBD of $50 g$ block:
$T_{1} - 50 g = 50 a$
From FBD of $100 g$ block:
$T_{2} - T_{1} - 100 g s i n 30^{\circ} = 100 a$
From FBD of $500 g$ block:
$500 g - T_{2} = 500 a$
$a = \frac{8 g}{13}$ downwards for $500 g$ block

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