Question

Find the acceleration of the moon with respect to the earth from the following data : Diistance between the earth and the moon = $3.85\times {10}^5$km and the time taken by the moon to complete one revolution around the earth = 27.3 days.

Answer 1

Distance between earth and Moon

$r=3.85\times {10}^{5}km=3.85\times {10}^{8}mT=27.3\text{days}=24\times 3600\times \left(27.3\right)sec=2.36\times {10}^{6}secv=\frac{2\pi r}{T}=\frac{2\times 3.14\times 3.85\times {10}^8}{2.36\times {10}^6}=1025.42m/sec\alpha =\frac{v^2}{r}=\frac{(1025.42{)}^2}{3.85\times {10}^8}=0.00273m/se{c}^2=2.66\times {10}^{-3}m/se{c}^2$