Find the acceleration of the two bodies if the system is shown, is initially at rest. Take g=10m/s2.
A
aA=aB=2m/s2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
aA=aB=1m/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
aA=aB=4m/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
aA=aB=3m/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is AaA=aB=2m/s2 The FBDs of the blocks are as shown
From the FBDs we have N1=10g=100N fmax=μN1=0.5×100=50N N2=N1+20g=100+200=300N
Assuming the block to move together with common acceleration, then ac=FmA+mB=6010+20=2m/s2
From the FBD of block B we have f=mBac=20ac=20×2=40N
Since, f<fmax, it means our assumption is right.
Hence, the blocks will move together with ac=2m/s2