Question

Find the additive inverse of: $1+\pi$

Answer 1

We know that the additive inverse of a number $x$ is $-x$, which when added to $x$ yields the additive identity $0$ that is

$x+(-x)=x-x=0$

Now, since

$(1+\pi )+[-(1+\pi \left)\right]=1+\pi -1-\pi =0$

Hence, the additive inverse of $(1+\pi )$ is $-(1+\pi )$.