Question

Find the additive inverse of:

(i) 5
(ii) −9
(iii) $\frac{3}{14}$
(iv) $\frac{-11}{15}$
(v) $\frac{15}{-4}$
(vi) $\frac{-18}{-13}$
(vii) 0
(viii) $\frac{1}{-6}$

Answer 1

(i) Additive inverse of 5 is −5.

(ii) Additive inverse of −9 is 9.

(iii) Additive inverse of $\begin{array}{l}\frac{3}{14}is\frac{-3}{14}\\ \end{array}$.

(iv) Additive inverse of $\frac{-11}{15}is\frac{11}{15}$.

(v) Additive inverse of $\frac{15}{-4}=\frac{15\times (-1)}{(-4)\times (-1)}$

$$\begin{gathered} =\frac{-15}{4} \\ =\frac{15}{4} \end{gathered}$$

(vi) Additive inverse of $\frac{-18}{-13}=\frac{-18\times (-1)}{(-13)\times (-1)}$
$$\begin{gathered} =\frac{18}{13} \\ =\frac{-18}{13} \end{gathered}$$

(vii) Additive inverse of​ 0 is 0.

(viii) Additive inverse of $\frac{1}{-6}=\frac{1\times (-1)}{(-6)\times (-1)}$
$$\begin{gathered} =\frac{-1}{6} \\ =\frac{1}{6} \end{gathered}$$