wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the adjoint of 112302103

Open in App
Solution

Let,
A=∣ ∣112302103∣ ∣
Let the minors,
M11=0,M12=11,M13=0
M21=3,M22=1,M23=1
M31=2,M32=4,M33=4
Therefore,
adjA=M11M21M31M12M22M32M13M23M33
=0321114014

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Adjoint and Inverse of a Matrix
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon